MAT 102
posted by Hannah on .
What is the domain of "p" when p(x)=x squared2x+4

write exponents this way:
p(x) = x^2  2x + 4
since "p" is the dependent variable, we usually use the word "range" instead of domain.
Domain would be your choice of the independent variable, that is, the x in this case.
anyway...
the x of the vertex is b/(2a) for f(x) = ax^2 + bx + c
so the x of the vertex is 2/2 = 1
p(1) = 12+4 = 3
so the range of the function is p(x) ≥ 3