Posted by **Hannah** on Thursday, October 3, 2013 at 7:32pm.

What is the domain of "p" when p(x)=x squared-2x+4

- MAT 102 -
**Reiny**, Thursday, October 3, 2013 at 7:54pm
write exponents this way:

p(x) = x^2 - 2x + 4

since "p" is the dependent variable, we usually use the word "range" instead of domain.

Domain would be your choice of the independent variable, that is, the x in this case.

anyway...

the x of the vertex is -b/(2a) for f(x) = ax^2 + bx + c

so the x of the vertex is 2/2 = 1

p(1) = 1-2+4 = 3

so the range of the function is p(x) ≥ 3

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