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May 6, 2016

Posted by Samantha on Wednesday, October 2, 2013 at 11:11pm.

Could someone tell me if I'm right, and if not what the correct answer is? Thank you! I'd appreciate an explanation, too, if you could. :)

1. Suppose you're given the following table of values for the function f(x),and you're told that the function is even:

x f(x)
-------------
–2 5
–0.35 –3
0 2
0.53 2
1 –5
Then:

f(2)= –5

f(.35) +f(–.53) = 1

***f(–1) – f(2) = –10

f(0) +f(–.53) = 0

Something is wrong. Given the table of values, the function can't be even.

2. Suppose you're given the following table of values for the function f(x), and you're told that the function is odd:

x f(x)
---------------
–2 5
–0.35 –3
0 2
0.53 2
1 –5
Then:

f(2)= 5

f(0.35) + f(–0.53) = –1

f(–1) – f(2) = –10

f(0) + f(–0.53) = 0

***Something is wrong. Given the table of values, the function can't be odd.
• Calculus, check my answers, please! - Steve, Wednesday, October 2, 2013 at 11:58pm

#1
The table of values is consistent with an even function. They don't provide f(x) and f(-x) for any value of x.

f(-1) - f(2) = f(1)-f(-2) = -5-5 = -10

#2
The table is ok, for the same reason as given for #1.

f(0) + f(–0.53) = f(0)-f(0.53) = 2-2 = 0

• Calculus, check my answers, please! - holly, Thursday, October 3, 2013 at 3:43pm

f(-1)=5 and f(-2)=-5 so 5--5 = 5+5= 10 that is how it is even