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September 30, 2014

September 30, 2014

Posted by **Rebekah** on Wednesday, October 2, 2013 at 5:59pm.

f(x)= 1/(4u^2-3)^2

- Calc -
**Steve**, Wednesday, October 2, 2013 at 7:25pmf(u) = (4u^2-3)^-2

f' = -2(4u^2-3)(8u)

= -16u(4u^2-3)^-3

f" = -16(4u^2-3)^-2 + 48u(8u)(4u^2-3)^-4

= 16(20u^2+3)(4u^2-3)^-4

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