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posted by Rebekah Wednesday, October 2, 2013 at 5:59pm.

find the second derivative f(x)= 1/(4u^2-3)^2

f(u) = (4u^2-3)^-2 f' = -2(4u^2-3)(8u) = -16u(4u^2-3)^-3 f" = -16(4u^2-3)^-2 + 48u(8u)(4u^2-3)^-4 = 16(20u^2+3)(4u^2-3)^-4

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