Posted by Kirandeep on Wednesday, October 2, 2013 at 5:22pm.
Find three consecutive integers such that nine less than three times the third is seven more than the sum of the first and second.

Math  herp_derp, Wednesday, October 2, 2013 at 6:31pm
ahh...those algebra days...
so, anyways, here's what u do...
1) identify the variables:
Let the 1st integer be "x"
Let the 2nd integer be "(x+1)"
Let the 3rd integer be "(x+2)"
2) now, set up the equation...
3(x+2)  9 = x + (x+1)
3) SOLVE away!!! :D
3x + 6  9 = 2x + 1
3x  3 = 2x + 1
x = 4
4) NOW the three consecutive integers will be...
{ 4, 5, 6, }

YAY, the answer :D
now, DON'T FORGET TO HERP THE DERP!!!

Math  Steve, Wednesday, October 2, 2013 at 7:27pm
solve as above, but don't forget the "seven more..."
3(x+2)  9 = x + (x+1) + 7
Answer This Question
Related Questions
 algebra  Five times the smallest of three consecutive odd integers is ten more ...
 math/algebra  Determine three consecutive odd integers such that three times ...
 Mathematics  Find three consecutive integers such that the sum of the first and...
 math  Find three consecutive odd integers such that twice the sum of the first ...
 Math  Find three consecutive integers such that the sum of the first and second...
 Algebra 2  Find three consecutive odd positive integers such that 3 times the ...
 Math please help  Three consecutive odd intergers are such that the sum of the ...
 quad. eq.  find 3 consecutive integers such that the product of the second and ...
 Math  find three consecutive even intergers for which the sum of the first two ...
 math  find three consecutive odd integers such that the sum of the first and ...
More Related Questions