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Idontgetit

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At 1650 °C the value of Kc for the equilibrium represented by the balanced equation is 2.38 x 10-1. Calculate the value of Kp at the same temperature. Express answer in scientific notation.

CO(g)+H2O(g) = CO2(g)+H2(g)

___ x 10 ____

  • Idontgetit - ,

    As I remember,

    Kp=Kc * (RT)n where n is equal to the sum of moles on products side minus total moles on reactants side.

  • Idontgetit - ,

    I would make a quick guess it is 0.238. Why?
    Kp = Kc(RT)^delta n
    where dn = nproducts - nreactants.
    I see 2 mols on the right and 2 mols on the left which means dn = 0, RT raised to the zero power is 1; bingo.

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