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October 20, 2014

October 20, 2014

Posted by **Samantha** on Wednesday, October 2, 2013 at 12:28pm.

1. Suppose that f is an even function whose domain is the set of all real numbers. Then which of the following can we claim to be true?

***The function f has an inverse f –1 that is even.

The function f has an inverse f –1, but we can't tell whether it's even or odd.

The function f has an inverse f –1, but we can't tell whether it's even or odd.

f –1 is not a function.

We can't tell whether or not f has an inverse.

2. Suppose that f is an odd function whose domain is the set of all real numbers. Then which of the following can we claim to be true?

(Points : 1)

The function f has an inverse f –1 that is even.

***The function f has an inverse f –1 that is odd.

The function f has an inverse f –1, but we can't tell whether it's even or odd.

The function f does not have an inverse.

We can't tell whether f has an inverse that's still a function.

- Calculus, check my answers, please! 3 -
**Steve**, Wednesday, October 2, 2013 at 1:32pm#1. f^-1 is not a function

Think of y = x^2

every value of y has two values of x.

#2 correct

- Calculus, check my answers, please! 3 -
**Samantha**, Wednesday, October 2, 2013 at 8:00pmHmm... Okay! I see how that works now! :) Thank you so much! I'll be posting a few more problems and would appreciate if you could help with those, too!

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