Tuesday

July 29, 2014

July 29, 2014

Posted by **Rebekah** on Wednesday, October 2, 2013 at 11:10am.

1) f(u)= 1/ (2u^2-1)^2

- calculus -
**Jai**, Wednesday, October 2, 2013 at 11:24amd/du ( 1/(2u^2 - 1)^2 )

d/du ( (2u^2 - 1)^-2 )

= -2(4u)(2u^2 - 1)^-3

= -8u / (2u^2 - 1)^3

Hope this helps~ :3

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