posted by asanda on .
calculate the mass and volume of oxygen released when 29;4g potassium chlorate decomposes to form potassium chloride and oxygen
The equation is
2KClO3 ==> 2KCl + 3O2
This is done the same way as the SO2 problem. Just follow the steps to obtain the mass of O2.
Do you want that volume at STP? I assume so. Remember that 1 mol of any gas occupies 22.4 L. You know how many mols O2 you have. mols O2 x (22.4L/mol) = ?L