calculate the mass and volume of oxygen released when 29;4g potassium chlorate decomposes to form potassium chloride and oxygen
How to calculate the volume and mass of oxygen realesead when 29.4g potassium chlorate decomposes to form potassium chloride and oxygen
The equation is
2KClO3 ==> 2KCl + 3O2
This is done the same way as the SO2 problem. Just follow the steps to obtain the mass of O2.
Do you want that volume at STP? I assume so. Remember that 1 mol of any gas occupies 22.4 L. You know how many mols O2 you have. mols O2 x (22.4L/mol) = ?L
how do we calculate the mass and volume of oxygen released when 29,4 g potassium chlorate decomposes to form chloride and oxygen??
7,16
44.8L
To calculate the mass and volume of oxygen released during the decomposition of potassium chlorate, we need to use the molar mass and the stoichiometry of the reaction.
First, let's write the balanced chemical equation for the decomposition of potassium chlorate (KClO3):
2KClO3 → 2KCl + 3O2
In this equation, we see that for every 2 moles of potassium chlorate (KClO3), 3 moles of oxygen (O2) are produced.
1. Calculating the moles of potassium chlorate:
To calculate the number of moles of potassium chlorate, we divide the given mass of potassium chlorate (29.4g) by its molar mass.
The molar mass of potassium chlorate (KClO3) can be calculated by adding up the atomic masses of its elements:
Molar mass(KClO3) = [molar mass(K) + molar mass(Cl) + 3 × molar mass(O)]
= [39.1 g/mol + 35.5 g/mol + 3 × 16.0 g/mol]
= 122.6 g/mol
Moles of potassium chlorate = mass / molar mass
= 29.4 g / 122.6 g/mol
≈ 0.24 mol
2. Calculating the moles of oxygen:
From the balanced chemical equation, we know that for every 2 moles of potassium chlorate, 3 moles of oxygen are produced.
Moles of oxygen = (moles of potassium chlorate) × (moles of oxygen / moles of potassium chlorate)
= 0.24 mol × (3 mol O2 / 2 mol KClO3)
= 0.36 mol
3. Calculating the mass of oxygen:
To calculate the mass of oxygen, we multiply the number of moles of oxygen by its molar mass.
The molar mass of oxygen (O2) is approximately 32.0 g/mol.
Mass of oxygen = moles of oxygen × molar mass of oxygen
= 0.36 mol × 32.0 g/mol
= 11.52 g
Therefore, the mass of oxygen released is approximately 11.52 grams.
4. Calculating the volume of oxygen:
To calculate the volume of oxygen released, we can use the ideal gas law, which states: PV = nRT.
Assuming the temperature (T) and pressure (P) remain constant, we can rearrange the formula to solve for the volume (V):
V = nRT / P
Where:
n = number of moles of oxygen
R = ideal gas constant (approximately 0.082 atm·L/mol·K)
T = temperature in Kelvin
P = pressure in atmospheres
Without knowing the temperature and pressure values, it is not possible to calculate the volume of oxygen released accurately using the ideal gas law.