Posted by **Ann** on Monday, September 30, 2013 at 11:15pm.

A ball is thrown up at the edge of a 364 foot cliff. The ball is thrown up with an initial velocity of 72 feet per second.

Its height measured in feet is given in terms of time t, measured in seconds by the equation h=−16t2+72t+364.

How high will the ball go?

To get how high the ball will go, am I supposed to factor −16t2+72t+364 or something?

- Pre-Calculus -
**Ann**, Monday, September 30, 2013 at 11:21pm
Sorry, the equation is −16t^2+72t+364

- Pre-Calculus -
**Steve**, Monday, September 30, 2013 at 11:22pm
nah. just recognize it's a parabola. Find the vertex. That will tell you how long it takes to get to its highest altitude. Then plug that value in for t in h(t) as given.

Finding the vertex of a parabola is easy, right. Algebra I.

- Pre-Calculus -
**Ann**, Monday, September 30, 2013 at 11:34pm
oh ok. But if I wanted to find how long it takes the ball to come back to the ground then I would have to factor it right?

- Pre-Calculus -
**Steve**, Monday, September 30, 2013 at 11:39pm
well, you could, or just use the Quadratic Formula. If you want to factor it, then we have

-16t^2+72t+364

-4(4t^2-18t-91)

Hmmm. Better stick with the QF.

- Pre-Calculus -
**Ann**, Monday, September 30, 2013 at 11:52pm
thanks

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