While exploring the canopy of the rainforest in equatorial South America, Anastasia falls from a branch 43.0 meters high. Exactly 1.6 seconds later Joe falls from the same branch. How high above the ground is Joe when Anastasia splats into the mud below?
time to fall Aastasia; h=1/2 g t^2 solve for t.
Now, subtract 1.6 from that. That gives the falling time for Joe.
h'=43-1/2(9.8)t^2
thanks!
To calculate the height above the ground where Joe is when Anastasia splats into the mud below, we need to use the equations of motion.
The equation for the height of an object in free fall is given by:
h = (1/2) * g * t^2
where:
h is the height
g is the acceleration due to gravity (approximately 9.8 m/s^2)
t is the time elapsed
Let's calculate the height of Anastasia when she hits the ground:
Using the equation, h = (1/2) * g * t^2, where h is 43.0 meters and t is 1.6 seconds.
h = (1/2) * 9.8 * (1.6)^2
h = 0.5 * 9.8 * 2.56
h = 12.64 meters
So, Anastasia falls approximately 12.64 meters before hitting the ground.
Now, let's calculate Joe's height above the ground when Anastasia hits the ground. Since Joe falls after 1.6 seconds, we need to subtract 1.6 seconds from the total time.
Using the same equation, h = (1/2) * g * t^2, where h is the unknown height and t is (1.6 - 1.6) = 0 seconds.
h = (1/2) * 9.8 * (0)^2
h = 0 * 0
h = 0 meters
Therefore, Joe is at a height of 0 meters above the ground when Anastasia splats into the mud below.