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Posted by on Monday, September 30, 2013 at 5:13pm.

it says "how many joules of energy would be required to heat 29.8 grams of carbon from 25.5 C to 79.3 C. (s= .71 Joules / grams times carbon) & the formula is Q= M x C x delta T .

  • chemistry - , Monday, September 30, 2013 at 5:22pm

    What's your problem? You have the formula and the numbers. Plug and chug.

  • chemistry - , Monday, September 30, 2013 at 5:27pm

    How?

  • chemistry - , Monday, September 30, 2013 at 5:36pm

    q = ?
    m = mass = 29.8 grams
    c = specific heat = .71 J/g*C
    delta T = 79.3-25.5 = 53.8

    q = 29.8 x 0.71 x 53.8 = ? joules.

    It would be helpful if you told me why you couldn't do that, please.

  • chemistry - , Monday, September 30, 2013 at 5:42pm

    So the answer would be 1233.5 joules?

  • chemistry - , Monday, September 30, 2013 at 5:50pm

    Not according to my calculator. Did you punch in the right numbers?

  • chemistry - , Monday, September 30, 2013 at 5:58pm

    Yeah. What did you get?

  • chemistry - , Monday, September 30, 2013 at 6:04pm

    1138.3004?

  • chemistry - , Monday, September 30, 2013 at 6:06pm

    You couldn't have.
    29.8 x 0.71 x 53.8 = 1138.3 J. If you typed the problem in right and that's 0.71 the answer should be rounded to 2 s.f. which is 1.1E3 J. If that was really 0.710 then the answer should be rounded to 1.14E3 J.
    It still would be helpful to know the real problem here. I hope this isn't a case of just not doing the work and getting someone on line to do it for you.

  • chemistry - , Monday, September 30, 2013 at 6:12pm

    1138.3004 is right. Now round it to either two or three s.f. depending upon how many you have in that 0.710 number.

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