Sunday

November 23, 2014

November 23, 2014

Posted by **Jesse** on Monday, September 30, 2013 at 2:35pm.

Historically, if a random individual comes to rent a vehicle, the following probabilities apply:

P(CC) = 0.16

P(MC) = 0.38

P(SUV) = 0.12

P(V) = 0.24

1. Find the probability that an individual would rent a sport utility vehicle (SUV) or a van (V). Show your answer as a decimal. Do not show the answer as a probability.

2. Find the probability that an individual does not rent a midsize car (MC). Show your answer as a decimal; do not show your answer as a percent.

3. Consider the next three individuals who rent cars. (Assume they come in randomly and do not know each other.) Find the probability that none of the three rents a midsize car (MC). Show your results as a decimal rounded to six decimal places; do not show your answer as a percent.

4. Consider the next three individuals who rent cars. (Assume they come in randomly and do not know each other.) Find the probability that at least one of the three individuals would rents a compact car (CC). Show your answer to 6 decimal places. Do not show the answer as a percent.

5. Two people arrive to rent cars. What is the probability that neither person rents a sport utility van (SUV)? Show your answer as a decimal with four decimal places; do not show your answer as a percent.

I am lost on how to find the answer to these questions...

- Statistics -
**PsyDAG**, Monday, September 30, 2013 at 2:57pmProbabilities only add to .90. Is the remaining .10 people who decided not to rent, or do you have a typo?

1. Either-or probabilities are found by adding the individual probabilities.

2. .16 + .12 + .24 = ?

3. If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events.

(answer to 2)^3 = ?

4. At least one = one, two or all rent CC. Use principles above.

5. Use principles above.

- Statistics -
**Jesse**, Monday, September 30, 2013 at 4:04pmNo typo, that is how the question reads.

Can you check my answers?

1. 0.54

2. 0.52

3. 0.140608

4. 0.405224

5. 0.4746

- Statistics -
**PsyDAG**, Tuesday, October 1, 2013 at 8:08pm1. SUV = .12, V = .24.

.12 + .24 ≠ .54

2. right

3. right, however, there is a problem with the missing .10. If it is included, it would be (1-.38)^3. = .62^3 = .388244

4. .16 + .16^2 + .16^3 = .238328

5. again to include the .10, (1-.12)^2 = .88^2 = .7744

**Answer this Question**

**Related Questions**

SUVs and Cars (Math) - In a parking lot, the # of ordinary cars is larger than ...

math - Assume that you are to pick 3 cars from the motor pool, which contains 6 ...

math - For this problem, assume that you are to pick 3 cars from the motor pool...

MATH - IF XYZ AUTO CO SOLD 23,000 VEHICLES IN 1999, HOW MANY WERE SUV'S? IF 7,...

Math Modeling - How is the number of cars and other vehicles changing over time...

Math - On a certain road 20% of the vehicles are trucks, 16% are buses and the ...

5TH GRADE MATH - SIXTY-SEVEN STUDENTS ARE GOING ON A FIELD TRIP TO THE ZOO. THE ...

physics - Consider two cars, one a compact model (m = 781 kg) and the other an ...

Statistics - A car rental agency currently has 41 cars available, 28 of which ...

Math-Algebra - The Toyota Co. has a daily production quota of $100,000 worth of ...