A bus travels 290 km south along a straight path with an average velocity of 81 km/h to the south. The bus stops for 25 min, then it travels 210 km south with an average velocity of 80 km/h to the south. How Long does it lasts ? Answer in units of h . What is the average velocity for the total trip? Answer in units of km/h
a. T=290km/81km/h + 210km/80km/h + 25/60 = 6.62 h.
b. V = d/T = (290+210)/6.62 = 75.5 km/h.
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To find out how long the entire trip lasts, we need to calculate the total time it takes for the bus to travel the first and second distances separately and then add them up.
First, let's calculate the time taken for the bus to travel 290 km at an average velocity of 81 km/h:
We can use the formula: time = distance / velocity
So, the time taken for the first leg of the trip is:
time = 290 km / 81 km/h ≈ 3.58 hours
Next, let's calculate the time taken for the bus to travel 210 km at an average velocity of 80 km/h:
Again, using the formula: time = distance / velocity
So, the time taken for the second leg of the trip is:
time = 210 km / 80 km/h ≈ 2.63 hours
Now, let's find the total time of the trip by adding the times for the two legs:
total time = 3.58 hours + 2.63 hours ≈ 6.21 hours
Therefore, the trip lasts approximately 6.21 hours.
To find the average velocity for the total trip, we need to calculate the total distance traveled and the total time taken:
The total distance traveled is 290 km + 210 km = 500 km
The total time taken is 6.21 hours
Now, we can use the formula: average velocity = total distance / total time
So, the average velocity for the total trip is:
average velocity = 500 km / 6.21 hours ≈ 80.32 km/h
Therefore, the average velocity for the total trip is approximately 80.32 km/h.