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December 22, 2014

December 22, 2014

Posted by **kristine Ramos** on Monday, September 30, 2013 at 8:45am.

- MATH -
**Graham**, Monday, September 30, 2013 at 11:35amLet N = a.bcd

c = d+3 -> 3 ≤ c ≤ 9

b = c-2 -> 1 ≤ b ≤ 7

a = b+c

a = 2c-2 -> 4 ≤ a ≤ 8

c = (a+2)/2 -> 3 ≤ c ≤ 5

.:

c = 3, N= 4.130...

c = 4, N= 6.241...

c = 5, N= 8.352...

Though of course the rules only fix the first four significant figures.

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