Posted by **denim** on Sunday, September 29, 2013 at 9:20pm.

Repeated die toss experiment. A fair die is tossed repeatedly, and the sequence of numbers that turn up is recorded, until a 1 is

obtained. When a 1 is obtained, the experiment is over, but the 1 is included in the sequence. Thus every outcome is a sequence of integers ending

in 1. Let X be the sum of the sequence of numbers obtained in the experiment. So the smallest possible value of X is 1, corresponding to the outcome

in which a 1 is obtained on the first toss.

Compute P(X=5).

- Stats/ Probability -
**PsyDAG**, Monday, September 30, 2013 at 2:38pm
Probability of NOT getting a 1 = 5/6, getting a 1 = 1/6.

If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events.

For five tosses:

(5/6)^4 * 1/6 = ?

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