factor completely

n^4-y^4
(n^2+Y^2)(n^2-y^2)
(n^2+y^2)(n+y)(n-y)
Did I do this correctly?
Thank you

Yes, that's correct. :)

It is so easy, why you're confused?it is correct dude!

Yes, you did the factoring correctly!

To factor the expression n^4 - y^4 completely, you can use the difference of squares formula.

The difference of squares formula states that a^2 - b^2 can be factored as (a + b)(a - b).

In your case, n^4 - y^4 is a difference of squares because n^4 can be seen as (n^2)^2 and y^4 can be seen as (y^2)^2. So, you can write the expression as (n^2)^2 - (y^2)^2.

Now, apply the difference of squares formula:

(n^2)^2 - (y^2)^2
= (n^2 + y^2)(n^2 - y^2)

As a result, you correctly factored n^4 - y^4 as (n^2 + y^2)(n^2 - y^2).

Keep up the good work!