A mixture of C3H8 and C2H2 has a mass of 2.6g . It is burned in excess O2 to form a mixture of water and carbon dioxide that contains 1.6 times as many moles of CO2 as of water.

Find the mass of C2H2 in the original mixture.

This solution is not right. I tried it several times and got the wrong answer

I don't need the percent of c2h2, i want the final mass.

Why did the molecule go to the comedy club?

Because it wanted to get a reaction!

Now let's solve your chemistry puzzle together.

Let's assume the mass of C3H8 in the mixture is 'x' grams, and the mass of C2H2 is 'y' grams.

The molar mass of C3H8 is 44 g/mol, and the molar mass of C2H2 is 26 g/mol.

So, the number of moles of C3H8 can be calculated using the equation:
moles of C3H8 = mass of C3H8 / molar mass of C3H8 = x / 44

Similarly, the number of moles of C2H2 can be calculated as:
moles of C2H2 = mass of C2H2 / molar mass of C2H2 = y / 26

According to the problem, the number of moles of CO2 is 1.6 times the number of moles of water.

Considering the balanced chemical equation for the combustion of C3H8 and C2H2, we know that:
1 mole of C3H8 produces 3 moles of CO2 and 4 moles of H2O

So, we can write the equation as:
moles of CO2 = 3 * (moles of C3H8 + moles of C2H2)

moles of water = 4 * (moles of C3H8 + moles of C2H2)

Given that moles of CO2 is 1.6 times the moles of water, we get:
1.6 * (moles of water) = moles of CO2

Substituting the values we found earlier, we can write:
1.6 * 4 * (moles of C3H8 + moles of C2H2) = 3 * (moles of C3H8 + moles of C2H2)

Simplifying the equation, we get:
6.4 * moles of C3H8 + 6.4 * moles of C2H2 = 3 * moles of C3H8 + 3 * moles of C2H2

Rearranging the terms, we get:
3.4 * moles of C3H8 = 3.4 * moles of C2H2

Canceling out the common factor:
moles of C3H8 = moles of C2H2

Since we know that the mass of the mixture is 2.6 grams, we can write an equation for the total mass:
x + y = 2.6

Since moles of C3H8 = moles of C2H2, we can rewrite the equation as:
(x/44) = (y/26)

Now we have two equations:
x + y = 2.6
(x/44) = (y/26)

Let's solve these equations together using our mathematical skills. But remember, I'm here to make you smile, not crunch numbers in silence! So, are you ready? Let's go!

To find the mass of C2H2 in the original mixture, we need to start by determining the number of moles of C2H2 and C3H8 in the mixture.

Let's assume the number of moles of C3H8 is x, and the number of moles of C2H2 is y.

The molecular weight of C3H8 is (3*12.01 + 8*1.01) g/mol = 44.11 g/mol.
The molecular weight of C2H2 is (2*12.01 + 2*1.01) g/mol = 26.04 g/mol.

The total mass of C3H8 in the mixture can be calculated by multiplying the number of moles (x) by the molecular weight (44.11 g/mol), which gives 44.11x grams.

Similarly, the total mass of C2H2 in the mixture can be calculated by multiplying the number of moles (y) by the molecular weight (26.04 g/mol), which gives 26.04y grams.

Given that the total mass of the mixture is 2.6 grams, we can write the following equation:

44.11x + 26.04y = 2.6 (Equation 1)

Next, we're given that the resulting mixture of water and carbon dioxide contains 1.6 times as many moles of CO2 as of water. Let's assume that the number of moles of water is z, so the number of moles of carbon dioxide is 1.6z.

The molecular weight of H2O is (2*1.01 + 16.00) g/mol = 18.02 g/mol.
The molecular weight of CO2 is (12.01 + 2*16.00) g/mol = 44.01 g/mol.

The total mass of water in the resulting mixture can be calculated by multiplying the number of moles (z) by the molecular weight (18.02 g/mol), which gives 18.02z grams.

Similarly, the total mass of carbon dioxide in the resulting mixture can be calculated by multiplying the number of moles (1.6z) by the molecular weight (44.01 g/mol), which gives 44.01(1.6z) grams.

Given that the total mass of the resulting mixture is 2.6 grams, we can write the following equation:

18.02z + 44.01(1.6z) = 2.6 (Equation 2)

Now we have two equations (Equation 1 and Equation 2) with two unknowns (x and y). We can solve these equations simultaneously to find the values of x and y, which will allow us to determine the mass of C2H2 in the original mixture.

Once we have the values of x and y, we can calculate the mass of C2H2 by multiplying the number of moles of C2H2 (y) by its molecular weight (26.04 g/mol).

Two equations in two unknowns. Solve them simultaneously. I think the chemistry is straight forward but the math may be a little tedious.

The combustion equations are as follows:
C3H8 + 5O2 ==> 3CO2 + 4H2O
2C2H2 + 5O2 ==> 4CO2 + 2H2O
Confirm that those are correct.

Let x = mass C3H8
and y = mass C2H2
---------------------
x + y = 2.6
Here is how you get the second equation.
mols CO2 = 1.6*mols H2O
mols CO2 = [(3x/44) + (4x/44)]
mols H2O = [(4y/2*26) + (2y/2*26)]
note: 44 is molar mass C3H8
and 26 is molar mass C2H2. All I've done is convert x grams CO2 and H2O to mols CO2 and H2O.
So the second equation is
[(3x/44) + (4x/44)= = 1.6*[(4y/2*26) + (2y/2*26)] and that can be simplified some to
(7x/44) =1.6*(6y/52).
Find y, then
%C2H2 = (y/2.6)*100 = ?
You should confirm all of this.