Friday

April 18, 2014

April 18, 2014

Posted by **Bridget** on Friday, September 27, 2013 at 11:50pm.

Width

Length

- Dma 040 -
**Jai**, Saturday, September 28, 2013 at 12:07amRepresent the unknowns with variables:

Let x = width

Let 2x + 7 = length (according to the first statement)

Then we set up the equation. To set up, we need to recall that the perimeter of a rectangle is given by

P = 2L + 2W

where L is length and W is width.

We know that P = 158. Substituting,

158 = 2(2x + 7) + 2x

We solve for x:

158 = 4x + 14 + 2x

158 - 14 = 6x

144 = 6x

x = 144/6

x = 24 ft (width)

2x+7 = 55 ft (length)

hope this helps~ :3

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