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March 26, 2017

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A skier is gliding along at 4.7m/s on horizontal, frictionless snow. He suddenly starts down a 10∘ incline. His speed at the bottom is 15m/s .

What is the length of the incline?
How long does it take him to reach the bottom?

  • Physics - ,

    L = (V^2-Vo^2)/2g
    a. L = (15^2-4.7^2)/19.6 = 10.4 m.

    b. h = L*sin10
    h = 10.4*sin10 = 1.8 m.

    h = Vo*t + 0.5g*t^2 = 1.8
    4.7t + 4.9t^2 = 1.8
    4.9t^2 + 4.7t - 1.8 = 0
    t = 0.293 s. Use Quadratic Formula.

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