Posted by Senu on .
A skier is gliding along at 4.7m/s on horizontal, frictionless snow. He suddenly starts down a 10∘ incline. His speed at the bottom is 15m/s .
What is the length of the incline?
How long does it take him to reach the bottom?
L = (V^2-Vo^2)/2g
a. L = (15^2-4.7^2)/19.6 = 10.4 m.
b. h = L*sin10
h = 10.4*sin10 = 1.8 m.
h = Vo*t + 0.5g*t^2 = 1.8
4.7t + 4.9t^2 = 1.8
4.9t^2 + 4.7t - 1.8 = 0
t = 0.293 s. Use Quadratic Formula.