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November 29, 2015
Posted by **Robin** on Friday, September 27, 2013 at 8:11pm.

- Calculus Please Help?? -
**bobpursley**, Friday, September 27, 2013 at 8:14pmHave you done the method of partial fractions yet?

- Calculus Please Help?? -
**Robin**, Friday, September 27, 2013 at 8:24pmYes, I know how to get variables. I got b=-8, c=1, and a=2, but I don't know how to get an integral as an answer. I need help integrating 2 other problems I will post as well, if you can help me.

- Calculus Please Help?? -
**Robin**, Friday, September 27, 2013 at 8:28pm1. (-5x^2+10x-12)/(x-5)(x^2+4)

2. (-8x-28)/((x-2)(x+9))

I know how to integrate, I just don't know how to get an integral, after finding a,b,c, and from that point

- Calculus Please Help?? -
**Reiny**, Friday, September 27, 2013 at 9:03pmSo you were able to use partial fractions to decompose it to

-8/(x-3)^2 + 2/(x-3) + 1/(x+2)

that was the hardest part, the rest is easy

isn't the integral of -8/(x-3)^2 equal to 8/(x-3) ?

as to the others, you should recognize the pattern of the derivative of a log function

recall that is y = ln (u)

then dy/dx = (du/dx) / ln (u)

so if we integrate

-8/(x-3)^2 + 1/(x+2) + 2/(x-3)

we get

8/(x-3) + ln(x+2) + 2ln(x-3) + constant

- Calculus Please Help?? -
**Reiny**, Friday, September 27, 2013 at 9:09pmFor your 2nd part,

did you get the partial fraction breakdown of

-2x/(x^2+4) - 3/(x-5) from (-5x^2 + 10x - 12)/((x-5)(x^2+4)) ?

then your integral would be

-ln(x^2+4) - 3ln(x-5) + a constant

let me know what you get for your last question.