Posted by chris on Friday, September 27, 2013 at 7:37pm.
The driver of a car, traveling at a constant 25 m/s, sees a child suddenly run into the road. It takes the driver 0.45s to hit the brakes. As it slows, the car has a steady acceleration of 8.5 m/s^2. What's the total distance the car moves before it stops?

physics  bobpursley, Friday, September 27, 2013 at 7:54pm
distance=vi(t+.45)1/2 a t^2
now, what is t?
vf=Viat solve for t, put it in the first equation.

physics  chris, Friday, September 27, 2013 at 8:03pm
So, 25(.45+.45)1/2(8.5)(.45)^2?

physics  bobpursley, Friday, September 27, 2013 at 8:20pm
yes, if you calculated time t right. I didn't check it.
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