Posted by **chris** on Friday, September 27, 2013 at 7:37pm.

The driver of a car, traveling at a constant 25 m/s, sees a child suddenly run into the road. It takes the driver 0.45s to hit the brakes. As it slows, the car has a steady acceleration of 8.5 m/s^2. What's the total distance the car moves before it stops?

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**bobpursley**, Friday, September 27, 2013 at 7:54pm
distance=vi(t+.45)-1/2 a t^2

now, what is t?

vf=Vi-at solve for t, put it in the first equation.

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**chris**, Friday, September 27, 2013 at 8:03pm
So, 25(.45+.45)-1/2(8.5)(.45)^2?

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**bobpursley**, Friday, September 27, 2013 at 8:20pm
yes, if you calculated time t right. I didn't check it.

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