physics
posted by chris on .
The driver of a car, traveling at a constant 25 m/s, sees a child suddenly run into the road. It takes the driver 0.45s to hit the brakes. As it slows, the car has a steady acceleration of 8.5 m/s^2. What's the total distance the car moves before it stops?

distance=vi(t+.45)1/2 a t^2
now, what is t?
vf=Viat solve for t, put it in the first equation. 
So, 25(.45+.45)1/2(8.5)(.45)^2?

yes, if you calculated time t right. I didn't check it.