physics
posted by Anonymous on .
A ball dropped from a sixth floor window accelerates at 10 m/s^2
After 2 seconds it hits the
ground. It bounces back with a
velocity of −15 m/s
1.find the height from which the ball was dropped.
2. How high did it bounce?

h=gt²/2 = 10•2²/2=20 m
v=gt =10•2 =20 m/s
v=v₀gt₁
v=0
t₁= v₀/g=15/10=1.5 s
h₁=v₀t₁gt₁²/2 =
=15•1.5 10•1.5²/2=11.25 m
a=Δv/Δt= (1520)/0.02=  1750 m/s