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August 31, 2014

August 31, 2014

Posted by **anna** on Wednesday, September 25, 2013 at 1:34pm.

- chemistry 1405 -
**DrBob222**, Wednesday, September 25, 2013 at 3:22pm_{88}Ra^{226}==>_{86}Rn^{222}+_{y}X^{z}

You want to determine y and z and X

Subscripts must add up and superscripts must add up.

Subscripts: On the left we have 88. On the right we have 86; therefore, y must be 2.

Superscripts: On the left we have 226 and on the right we have 222; therefore, z must be 4.

Which particle has a mass of 4 and an atomic number of 2? That must be He so that's X.

See how easy that is.

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