Posted by **anna** on Wednesday, September 25, 2013 at 1:34pm.

how to write a nuclear equation for the nuclear decay of Ra-226 to an isotope of radon-222

- chemistry 1405 -
**DrBob222**, Wednesday, September 25, 2013 at 3:22pm
_{88}Ra^{226} ==> _{86}Rn^{222} + _{y}X^{z}

You want to determine y and z and X

Subscripts must add up and superscripts must add up.

Subscripts: On the left we have 88. On the right we have 86; therefore, y must be 2.

Superscripts: On the left we have 226 and on the right we have 222; therefore, z must be 4.

Which particle has a mass of 4 and an atomic number of 2? That must be He so that's X.

See how easy that is.

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