A sprinter explodes out of the starting block with an acceleration of + 2.43 m/s2, which she sustains for 1.10 s. Then, her acceleration drops to zero for the rest of the race. What is her velocity at (a)t = 1.10 s and (b) at the end of the race?

To find the sprinter's velocity at (a)t = 1.10 s and (b) at the end of the race, we can break down the problem into two parts: the initial acceleration phase and the zero acceleration phase.

(a) At t = 1.10 s:
During the initial acceleration phase, the sprinter has an acceleration of +2.43 m/s^2 for 1.10 s. To find her velocity at this time, we use the equation:

v = u + a * t

Where:
v = Final velocity
u = Initial velocity (which we assume is zero since she starts from rest)
a = Acceleration
t = Time

Plugging in the values:
v = 0 + 2.43 * 1.10
v = 2.673 m/s

Therefore, her velocity at (a)t = 1.10 s is 2.673 m/s.

(b) At the end of the race:
After the initial acceleration phase, her acceleration drops to zero. This means she continues with a constant velocity after t = 1.10 s. Since her velocity is constant, it will be the same as the velocity at (a)t = 1.10 s.

Therefore, her velocity at the end of the race is also 2.673 m/s.

velocity = acceleration * time

her acceleration is zero for the rest of the race, so her velocity stays constant