What is the structure for ethyl ethanamide?

(Ie. c-c-N-c-c) ??? Thanks

Draw a representation of the resulting equilibrium mixture when ammonia is added to water. The equilibrium constant,K, is a small number for this reaction so represent that in your drawing.

2NH(g) + 2.5O2(g) ---><--- 2NO(g) + H2O(g) + Heat

Find out molarity of 20% NaoH (g/ml) solution of Na=23 , O=16, H=1

25

Ch3oh-ch3ch2oh

The structure for ethyl ethanamide, also known as N-ethylacetamide, is as follows:

CH3CH2-N-C(O)-CH3

To explain how to determine this structure, we start by understanding the molecular formula of ethyl ethanamide. The formula is C5H11NO, which suggests that it contains five carbon atoms (C5) with one oxygen (O) and one nitrogen (N) atom. The number of hydrogen (H) atoms, 11, can be calculated by subtracting the total number of other atoms from the total number of valence electrons in the molecule.

To determine the connectivity of these atoms, we can follow a few guidelines:

1. Carbon (C) atoms typically form four bonds and prefer to be in the center of organic molecules.
2. Nitrogen (N) atoms usually form three bonds, and oxygen (O) atoms typically form two bonds.
3. Hydrogen (H) atoms form a single bond.

Based on these guidelines, we can construct the structure:

1. Begin by placing the carbon atoms in a line, as there are five carbon atoms in the molecule: C-C-C-C-C.
2. Next, connect the C atoms by single bonds as carbon prefers four bonds:
CH3-CH2-CH2-CH2-CH3.
3. The nitrogen atom (N) will have a bond with one of the carbon atoms. In this case, we connect it to the first carbon atom: CH3CH2-N-CH2-CH2-CH3.
4. The oxygen atom (O) forms a bond with one of the carbon atoms and a double bond with the N atom. In this case, it forms a bond with the second carbon atom: CH3CH2-N-C(O)-CH2-CH3.
5. Finally, the third carbon atom forms a bond with the oxygen atom. In this case, it connects to the third carbon atom: CH3CH2-N-C(O)-CH3.

Therefore, the structure of ethyl ethanamide (N-ethylacetamide) is CH3CH2-N-C(O)-CH3.