the sum of three even consecutive integers if the first integer is y.
To find the sum of three even consecutive integers given that the first integer is y, we first need to determine the next two consecutive even integers.
Consecutive even integers follow a pattern where each integer is exactly 2 units greater than the previous one. Therefore, the second integer would be y + 2, and the third integer would be (y + 2) + 2, which simplifies to y + 4.
To find the sum of these three consecutive even integers, we add them together:
sum = y + (y + 2) + (y + 4)
Combining like terms, we get:
sum = 3y + 6
So, the sum of three even consecutive integers with the first integer being y is 3y + 6.
To find the sum of three even consecutive integers with the first integer as "y," you can follow these steps:
Step 1: Determine the consecutive even integers
Since we want consecutive even integers, we can start with the first integer, which is given as "y." Then we add 2 to get the next even integer and add 2 again to get the third even integer. So, the three consecutive even integers would be y, y+2, and y+4.
Step 2: Find the sum of the three integers
To find the sum of these three integers, you need to add them together:
Sum = y + (y+2) + (y+4)
Step 3: Simplify the expression
To simplify the expression, you can combine like terms by adding the variables and constants separately:
Sum = y + y + 2 + y + 4
Sum = 3y + 6
Therefore, the sum of the three even consecutive integers with the first integer as "y" is 3y + 6.