Wednesday
October 22, 2014

Homework Help: Chemistry

Posted by James on Sunday, September 22, 2013 at 10:28pm.

A sample of impure magnesium was analyzed by allowing it to react with excess HCl solution:

Mg(s) + 2 HCl(aq) → MgCl2(aq) + H2(g)

After 1.27 g of the impure metal was treated with 0.100 L of 0.768 M HCl, 0.0125 mol HCl remained. Assuming the impurities do not react, what is the mass % of Mg in the sample?

I converted the 1.27gMg to 0.0522moles Mg. Im just not sure where to go from there. please help me in the right direction.
Thanks!

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