Two cars, A and B, are traveling in the same direction, although car A is 204 m behind car B. The speed of A is 22.9 m/s, and the speed of B is 18.6 m/s. How much time does it take for A to catch B?
Da = 204 + Db
Da = 22.9t = 204 + 18.6t
22.9t-18.6t = 204
4.3t = 204
t = 47.44 s. To catch up.
To determine how much time it takes for car A to catch car B, we first need to find out the relative speed between the two cars. The relative speed is the difference in their speeds.
The speed of car A is 22.9 m/s, and the speed of car B is 18.6 m/s. Therefore, the relative speed between them is:
Relative speed = Speed of car A - Speed of car B
Relative speed = 22.9 m/s - 18.6 m/s
Relative speed = 4.3 m/s
Now that we know the relative speed, we can calculate the time it takes for car A to catch car B by using the formula:
Time = Distance / Speed
Since car A is 204 m behind car B, the distance it needs to cover to catch up is 204 m.
Time = 204 m / 4.3 m/s
Time ≈ 47.44 seconds
Therefore, it takes approximately 47.44 seconds for car A to catch car B.