1.) 28 - 0.3 = 0.7 - 12
2.) 3c -4c + 1 = 5c + 2 + 3
1 is not an equation.
2.
3c -4c + 1 = 5c + 2 + 3
-c + 1 = 5c + 5
-6c = 4
c = -2/3
1). 28 - 0.3y = 0.7y - 12
Regarding the second equation, how does -c become -6c?
28 - 0.3y = 0.7y - 12
28 + 12 = 0.7y + 0.3y
40 = y
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Regarding the second equation, how does -c become -6c?
I subtracted 5c from both sides of equation and combined like terms.
I subtracted 5c from both sides of equation and combined like terms.
1.) To solve the equation 28 - 0.3 = 0.7 - 12, we need to simplify the expressions on both sides and then isolate the variable.
Starting with the left side of the equation:
28 - 0.3 = 27.7
Next, we simplify the right side of the equation:
0.7 - 12 = -11.3
Now we have the equation 27.7 = -11.3. This equation does not have a solution because no number can be both 27.7 and -11.3 at the same time.
Therefore, the answer to the equation 28 - 0.3 = 0.7 - 12 is no solution.
2.) To solve the equation 3c - 4c + 1 = 5c + 2 + 3, we can simplify the expressions and combine like terms to isolate the variable.
Starting with the left side of the equation:
3c - 4c + 1 = -c + 1
Next, we simplify the right side of the equation:
5c + 2 + 3 = 5c + 5
Now we have the simplified equation -c + 1 = 5c + 5. To isolate the variable, we can move the terms involving c to one side and the constant terms to the other side.
Adding c to both sides:
-c + c + 1 = 5c + c + 5
1 = 6c + 5
Subtracting 5 from both sides:
1 - 5 = 6c + 5 - 5
-4 = 6c
Finally, dividing both sides by 6:
-4/6 = 6c/6
-2/3 = c
Therefore, the value of c that satisfies the equation 3c - 4c + 1 = 5c + 2 + 3 is c = -2/3.