How many sulfate ions are there in 2.500 mL of 5.0 x 10-15 moles of Cr2(SO4)3?
Three times as many.
To determine the number of sulfate ions in 2.500 mL of Cr2(SO4)3, we first need to calculate the number of moles of Cr2(SO4)3 in 2.500 mL.
Step 1: Convert mL to liters
2.500 mL ÷ 1000 = 0.002500 L
Step 2: Calculate the number of moles of Cr2(SO4)3
moles = volume (in liters) x concentration (in moles/liter)
moles = 0.002500 L x 5.0 x 10^-15 mol/L
Step 3: Multiply the number of moles of Cr2(SO4)3 by Avogadro's number to find the number of sulfate ions.
number of sulfate ions = moles of Cr2(SO4)3 x 6.022 x 10^23 mol^-1
Now, let's calculate the number of sulfate ions:
moles of Cr2(SO4)3 = 0.002500 L x 5.0 x 10^-15 mol/L = 1.250 x 10^-17 moles
number of sulfate ions = 1.250 x 10^-17 mol x 6.022 x 10^23 mol^-1
Calculating the number of sulfate ions:
number of sulfate ions = 7.527 x 10^6 sulfate ions
Therefore, there are approximately 7.527 x 10^6 sulfate ions in 2.500 mL of 5.0 x 10^-15 moles of Cr2(SO4)3.