If E represents a digit and the average of the two-digit numbers EE, 4E and E4 is 66, what is the average of 3E and E3 ?
so
(10E+E + 40 + E + 10E+4)/3 = 66
22E + 44 = 198
22E = 154
E = 7
So 3E = 37 and E3 = 73
average of 37 and 73 = 55
(10E+E + 40 + E + 10E+4)/3 = 66
22E + 44 = 198
22E = 154
E = 7
So 3E = 37 and E3 = 73
average of 37 and 73 = 55