Post a New Question

Posted by Anonymous on Friday, September 20, 2013 at 2:36pm.

If x varies inversely as y2 (y square) and x = 4 awhen y = 9, what is the value of y when x = 9?

x = k/y^2 4 = k/81 now you have k, so plug in your new x value to find y.

More Related Questions