What is the binding energy of 1 mole of 239/94 Pu if the mass defect is 0.001896 kg/mol?

To calculate the binding energy of 1 mole of 239/94 Pu, we need to use the Einstein's mass-energy equivalence formula, which states that E = mc^2. In this equation, E represents the binding energy, m is the mass defect, and c is the speed of light (approximately 3 x 10^8 m/s).

Given that the mass defect is 0.001896 kg/mol, we can substitute this value into the equation as follows:

E = (0.001896 kg/mol) * (3 x 10^8 m/s)^2

Calculating this equation will give us the binding energy per mole.

To calculate the binding energy of 1 mole of a nuclear isotope, you can make use of Einstein's mass-energy equation, E=mc^2, where E is the energy, m is the mass defect, and c is the speed of light (approximately 3 x 10^8 m/s).

First, convert the mass defect given in kg/mol into grams/mol:

0.001896 kg/mol = 1.896 g/mol

Next, convert the mass defect in grams into the number of moles using the molar mass of the isotope. In this case, the molar mass of 239/94 Pu is 239 g/mol.

Number of moles of 239/94 Pu = 1.896 g/mol ÷ 239 g/mol = 0.00793 mol

Now, multiply the number of moles by Avogadro's constant (6.022 x 10^23 mol^-1) to calculate the number of atoms:

Number of 239/94 Pu atoms = 0.00793 mol x 6.022 x 10^23 mol^-1 = 4.779 x 10^21 atoms

To find the binding energy of 1 mole of atoms, divide the mass defect by the number of atoms and multiply by c^2:

Binding energy of 1 mole of 239/94 Pu = (0.001896 kg/mol ÷ 4.779 x 10^21 atoms) x (3 x 10^8 m/s)^2

Now, you can calculate the binding energy by substituting the appropriate values into the equation:

Binding energy of 1 mole of 239/94 Pu ≈ 3.22 x 10^11 J/mol

What is E=massdefect*speedlight^2