Posted by **Frank** on Thursday, September 19, 2013 at 1:02pm.

How many grams of sodium sulphate (mol. wt. 142) are required to make 1.2 liters of 0.5N solution

- Chemistry -
**DrBob222**, Thursday, September 19, 2013 at 2:28pm
Technically one can't calculate this without knowing the reaction involved; however, is most problems of this type the usual is to use total + and - charge.

Therefore, equivalent weight Na2SO4 = molar mass/+ charge = 142/2 = 81.

How many equivalents do you need? That's

N x L = 0.5N x 1.2L = ?

Then ?equivalent x equivalent weight = grams Na2SO4.

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