posted by Anonymous .
Jack looks at a clock tower from a distance and determines that the angle of elevation of the top of the tower is 40°. John, who is standing 20 meters from Jack as shown in the diagram, determines that the angle of elevation to the top of the tower is 60°. If Jack’s and John’s eyes are 1.5 meters from the ground, how far is John from the base of the tower? Round your answer to the nearest tenth.
If the height of the tower is h higher than their eyes, and John is x away from the base,
h/x = tan 60°
h/(x+20) = tan 40°
Eliminating h, we get
x*tan60° = (x+20)*tan40°
Find x and add 1.5 to find the total height.
Thanks for the wrong answer
Thanks fot the wrong answer... really needed a negitave to my question...
Ghulam sees the school 800m in the distance. He looks up to the top of the school and the angle of elevation is 32 degrees. Of Ghulam eyes are 1.5 meters above the ground, what is the height of the school, to the nearest metre ?