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geometry

posted by on .

Given: FG (SEG) bisects BT (SEG)
BO=7x-6
OT=5x+10

Prove: BO=50

  • geometry - ,

    I think we need to see the figure, but looking at the given, I think the point FG bisects and intersects BT at point O. Therefore we can say the lengths of segments BO and OT are equal, or
    7x - 6 = 5x + 10
    7x - 5x = 10 + 6
    2x = 16
    x = 8

    Susbtituting,
    BO = 7x - 6
    BO = 7(8) - 6
    BO = 56 - 6
    BO = 50

    Hope this helps~ :3

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