Posted by **luis** on Thursday, September 19, 2013 at 2:22am.

Given: FG (SEG) bisects BT (SEG)

BO=7x-6

OT=5x+10

Prove: BO=50

- geometry -
**Jai**, Thursday, September 19, 2013 at 6:04am
I think we need to see the figure, but looking at the given, I think the point FG bisects and intersects BT at point O. Therefore we can say the lengths of segments BO and OT are equal, or

7x - 6 = 5x + 10

7x - 5x = 10 + 6

2x = 16

x = 8

Susbtituting,

BO = 7x - 6

BO = 7(8) - 6

BO = 56 - 6

BO = 50

Hope this helps~ :3

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