Thursday

December 18, 2014

December 18, 2014

Posted by **luis** on Thursday, September 19, 2013 at 2:22am.

BO=7x-6

OT=5x+10

Prove: BO=50

- geometry -
**Jai**, Thursday, September 19, 2013 at 6:04amI think we need to see the figure, but looking at the given, I think the point FG bisects and intersects BT at point O. Therefore we can say the lengths of segments BO and OT are equal, or

7x - 6 = 5x + 10

7x - 5x = 10 + 6

2x = 16

x = 8

Susbtituting,

BO = 7x - 6

BO = 7(8) - 6

BO = 56 - 6

BO = 50

Hope this helps~ :3

**Answer this Question**

**Related Questions**

geometry - Given: FG (SEG) bisects BT (SEG) BO=7x-6 OT=5x+10 Prove: BO=50

geometry - We are learning about proofs. We drew lines between noncollinear ...

Math - We are learning about proofs. We drew lines between noncollinear points. ...

Geometry Please Help - Given: QS bisects ∠RQT; ∠R ≅ ∠ T ...

geometry - Given: ABC,/ AD bisects <BAC, and /AE=/ED Prove: AE/AC = BD/BC

Geometry Please Help - Given: QS bisects ∠RQT; ∠R ≅ ∠ T ...

GEOMETRY - GIVEN: TRIANGLE ABC,AD bisects <BAC,and AE=ED, PROVE:AE/AC=BD/BC

Geometry - Given: angle BAC is congruent to angle ACD, segment BD bisects ...

Geometry - Given: ray AD bisects <BAC <DAC=3x, and <BAD=5x-24 Prove: x=...

Math (Geometry) - Given: ABCD is arhombus. prove:AC bisects angle BAD and angel...