Posted by luis on Thursday, September 19, 2013 at 2:22am.
Given: FG (SEG) bisects BT (SEG)
BO=7x6
OT=5x+10
Prove: BO=50

geometry  Jai, Thursday, September 19, 2013 at 6:04am
I think we need to see the figure, but looking at the given, I think the point FG bisects and intersects BT at point O. Therefore we can say the lengths of segments BO and OT are equal, or
7x  6 = 5x + 10
7x  5x = 10 + 6
2x = 16
x = 8
Susbtituting,
BO = 7x  6
BO = 7(8)  6
BO = 56  6
BO = 50
Hope this helps~ :3
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