Posted by luis on Thursday, September 19, 2013 at 2:21am.
Given: FG (SEG) bisects BT (SEG)
BO=7x6
OT=5x+10
Prove: BO=50

geometry  Graham, Thursday, September 19, 2013 at 3:08am
There appears to be insufficient information. Where is O, with respect to BT and FG?

geometry  Steve, Thursday, September 19, 2013 at 4:06am
It appears to me that O is midway between B and T. If so, then
7x6 = 5x+10
2x = 16
x = 8
So, BO = 5*8+10 = 50