Posted by **luis** on Thursday, September 19, 2013 at 2:21am.

Given: FG (SEG) bisects BT (SEG)

BO=7x-6

OT=5x+10

Prove: BO=50

- geometry -
**Graham**, Thursday, September 19, 2013 at 3:08am
There appears to be insufficient information. Where is O, with respect to BT and FG?

- geometry -
**Steve**, Thursday, September 19, 2013 at 4:06am
It appears to me that O is midway between B and T. If so, then

7x-6 = 5x+10

2x = 16

x = 8

So, BO = 5*8+10 = 50

## Answer This Question

## Related Questions

- geometry - Given: FG (SEG) bisects BT (SEG) BO=7x-6 OT=5x+10 Prove: BO=50
- geometry - We are learning about proofs. We drew lines between noncollinear ...
- Math - We are learning about proofs. We drew lines between noncollinear points. ...
- Geometry Please Help - Given: QS bisects ∠RQT; ∠R ≅ ∠ T ...
- geometry - Given: ABC,/ AD bisects <BAC, and /AE=/ED Prove: AE/AC = BD/BC
- Geometry Please Help - Given: QS bisects ∠RQT; ∠R ≅ ∠ T ...
- GEOMETRY - GIVEN: TRIANGLE ABC,AD bisects <BAC,and AE=ED, PROVE:AE/AC=BD/BC
- Geometry - Given: angle BAC is congruent to angle ACD, segment BD bisects ...
- Geometry - Given: ray AD bisects <BAC <DAC=3x, and <BAD=5x-24 Prove: x=...
- Math (Geometry) - Given: ABCD is arhombus. prove:AC bisects angle BAD and angel...

More Related Questions