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July 25, 2014

July 25, 2014

Posted by **adina** on Thursday, September 19, 2013 at 12:10am.

- precalc -
**Steve**, Thursday, September 19, 2013 at 12:15amassuming a rectangular fenced area, let

parallel length = x

area = x(1000-x)/3 = 1/3 (1000x-x^2)

Just figure where the vertex of the parabola is, and that will give you the maximum area.

- precalc -
**adina**, Thursday, September 19, 2013 at 12:39amwhere did you get the 1/3 from

- precalc -
**Graham**, Thursday, September 19, 2013 at 2:31amAssume the length of the fence opposite the barn side is: x.

The remaining (1000-x) feet of fence work is divided into three by the two other sides and the partition. Each being: (1000-x)/3.

The area of the pen is: y = x(1000-x)/3

The area is maximum when the derivative is zero. The derivative is:

y' = (1000-2x)/3

Solve for x when y' = 0.

- precalc -
**Steve**, Thursday, September 19, 2013 at 4:53amsince this was pre-calc, I assumed that calculus was not available. But the parabola's vertex is from back in Algebra I!

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