Wednesday

July 30, 2014

July 30, 2014

Posted by **Anonymous** on Wednesday, September 18, 2013 at 11:15am.

Factor the polynomials:

a) 3x^2 +19x - 40

b) x^4 - 25x^2

Simplify the expression completely:

(1/(x-h)^3 - 1/x^3)/8h

- Pre Calculus -
**bobpursley**, Wednesday, September 18, 2013 at 11:27amb. Difference of two squares, then one of those factors can be factored as a difference of two squares again. I can check your work.

a. What is ( x+8)(3x-5)

c. do some combination.

((x^3-(x-h)^3)/(8h(x^3*(x-h)^3)

now factor the numerator as a difference of two cubes. Doing it in my head, I see some reduction.

- Pre Calculus -
**Anonymous**, Wednesday, September 18, 2013 at 11:33amooh, nevermind I figured out how to do a) answer is 3(x-5)(x+8)....I forgot to move the 3 over

and b) uses the difference of squares formula so the answer is x^2(x-5)(x+5)

still can't figure out the third one though!

**Related Questions**

gnozahs - I removed about ten questions you posted this morning. There was no ...

Pre-Calculus - Can you show me how to find the rectangular equation: r=2cos(...

Math HELP PLEASE - 1.My family went to starbucks. My daughter and myself ordered...

Pre Calculus - Pre Calculus why is sin(-20)/cos 380 equal to tan (-200)

Pre-Calculus - I'm trying to finish up my pre-cal homework and I am stuck on 2 ...

Pre-Calculus - I'm trying to finish up my pre-cal homework and I am stuck on 2 ...

Pre-Calculus - I am in Honors Pre-Calculus and am having a hard time ...

To Akashdeep Singh - Since your question had to do with computer games, not ...

Pre Calculus 12 - Im going over my pre calculus 12 exam, and I need help with ...

Applied Calculus-Question for Damon - Hi, I have two other questions for Applied...