a bullet of mass 10gm travels horizentaly with v=100m/sec and it is absorted by wooden block of mass 990gm.suspended verticle height through which the block...?
To determine the vertical height through which the block will be suspended after the bullet is absorbed, we can use the law of conservation of momentum. The momentum before the collision is equal to the momentum after the collision.
The momentum of an object is defined as the product of its mass and velocity. So, we can calculate the initial momentum of the bullet and the final momentum of the bullet and the wooden block together.
Given:
Mass of the bullet (m1) = 10 g = 0.01 kg
Velocity of the bullet (v1) = 100 m/s
Mass of the wooden block (m2) = 990 g = 0.99 kg
Initial momentum of the bullet (P1) = m1 * v1
Final momentum of the bullet and wooden block (P2) = (m1 + m2) * vf
According to the conservation of momentum, P1 = P2
So, m1 * v1 = (m1 + m2) * vf
0.01 kg * 100 m/s = (0.01 kg + 0.99 kg) * vf
1 kg m/s = 1 kg * vf
vf = 1 m/s
The final velocity vf represents the upward velocity of the bullet and wooden block together just after the collision. Since the block will reach its maximum height at the point of zero velocity, we can use the equations of motion to calculate the vertical height (h) traveled by the block.
Using the equation: vf^2 = v^2 + 2a*h
Where vf = 0 m/s (at the highest point),
v = 1 m/s,
a = acceleration due to gravity (approx. 9.8 m/s^2),
h = vertical height
0^2 = 1^2 + 2 * 9.8 * h
0 = 1 + 19.6 * h
-1 = 19.6 * h
h = -1/19.6
The negative sign indicates that the height should be considered in the opposite direction of gravity. However, it doesn't make physical sense to have a negative height, so we disregard the negative sign.
Therefore, the vertical height through which the block will be suspended after the bullet is absorbed is approximately 0.051 m (or 5.1 cm).