please help me for this problem.im not good in math.the challenge involves in dealing with the owner is to use a 20 meter fencing material to build a pig pen so that the owner will not be buying any additional materials considering also that one side of the pen is the outside wall of his garage? what is the dimension of this pig pen?
It could be 8 by 6(2), 10 by 5(2) 0r some other combination. To maximize the area, you want to get it as close to a square as possible.
Kdkd
To solve this problem, we can use a little bit of algebra to determine the dimensions of the pig pen. Let's assume that the pig pen is in the shape of a rectangle.
Let's start by assigning variables to the dimensions of the pig pen. Let's call the length of the rectangle L and the width of the rectangle W. Since we are given that one side of the pen is the outside wall of the garage, we can say that the length of the rectangle is the same as the width of the garage.
Now, let's work on finding the perimeter of the pig pen, using the information provided. The perimeter of a rectangle is given by the formula: Perimeter = 2L + 2W. In this case, the given perimeter is 20 meters, so we can set up the equation:
2L + 2W = 20
Since we know that L = W, we can substitute L for W in the equation, which gives us:
2L + 2L = 20
4L = 20
L = 20/4
L = 5
Hence, the length of the pig pen is 5 meters. Since L = W, the width of the pig pen is also 5 meters.
Therefore, the dimensions of the pig pen are 5 meters by 5 meters.