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September 2, 2014

September 2, 2014

Posted by **Anon** on Wednesday, September 18, 2013 at 1:17am.

(a) How long it takes (in s) after the first can has been thrown into the air for the two cans to collide?

(b) Find the initial speed of the cans (in m/s).

- Classical Mechanics -
**Graham**, Wednesday, September 18, 2013 at 7:00amLet the height of the first can be x, that of the second can be y; and both cans be thrown at speed v.

x(t) = v t - g t^2 /2

y(t) = v (t-t1) - g (t-t1)^2 /2

Find t when x(t) = y(t) = h

From the first height equation:

v = h/t + gt/2

Substituted into the second.

h = (h/t + gt/2)(t-t1) - g(t-t1)^2/2

Simplify into a quadratic and solve for t.

...

Once you have t then use (from above):

v = h/t + gt/2

- Classical Mechanics -
**Anon**, Wednesday, September 18, 2013 at 2:37pmthank you it help me!

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