A professional golfer can hit a ball with a speed of 70 m/s. What is the maximum distance a golf ball hit with this speed could travel on Mars, where the value of g is 3.71 m/s^2?
To determine the maximum distance a golf ball hit with a speed of 70 m/s could travel on Mars, we need to consider the projectile motion of the ball in a gravitational field.
To find the range (maximum distance), we can use the formula:
range = (initial velocity^2 * sin(2 * theta)) / gravitational acceleration
where:
- initial velocity is the speed of the ball (70 m/s in this case)
- theta is the angle at which the ball is launched (assume it's launched at an angle of 45 degrees)
- gravitational acceleration is the acceleration due to gravity on Mars (3.71 m/s^2 in this case)
Plugging in the values, we have:
range = (70^2 * sin(2 * 45)) / 3.71
Calculating the expression, we get:
range ≈ 1015.97 meters
Therefore, the maximum distance a golf ball hit with a speed of 70 m/s could travel on Mars, where the value of g is 3.71 m/s^2, is approximately 1015.97 meters.