A student measures the volume of a liquid and finds it to be 40mL. How many significant figures are in the measurement?

1 ***
2
3
4

Calculate the area, with the appropriate number of significant figures, of a rectangular room that is 14.10 m wide by 15.0 m long.
212 m^2***
211.5 m^2
29.1 m
29.10 m

Am I right or wrong?

it is 212 m^2 i just took the quiz

I think you are right.

Many may argue with the first one and suggest 40 has two s.f. To have two, however, it should be written as 40. where the . is not the end of the sentence. To avoid confusion many would write that as 4E1 to show the one s.f. and not two.

Ok but in all I'm right?

That's what I said, you are right.

So the answer is A or is it B

For the first question, to determine the number of significant figures in a measurement, we look at the digits present in the number. Non-zero digits are always significant, so in the measurement of 40 mL, both digits (4 and 0) are non-zero and, therefore, significant. Therefore, the correct answer is 2.

For the second question, to calculate the area of a rectangle, we multiply the length by the width. To determine the appropriate number of significant figures in the area, we look at the original measurements.

In this case, the width is given as 14.10 m, which has four significant figures. The length is given as 15.0 m, which also has four significant figures. When multiplying these two measurements, we need to consider the least number of significant figures among the factors, which in this case is three (due to the measurement 15.0 m). Therefore, the area with the appropriate number of significant figures is 212 m^2.

Based on the given answers, you are correct in both cases.