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Posted by on Tuesday, September 17, 2013 at 10:45pm.

A rocket moves upward, starting from rest with an acceleration of 28.3 m/s2 for 5.50 s. It runs out of fuel at the end of the 5.50 s, but does not stop.
How high does it rise above the ground? Answer in units of m

  • Physics - , Saturday, September 21, 2013 at 3:51pm

    h1=a*t^2 = 28.3*5.5^2=856.1 m Above gnd.
    V1 = a*t = 28.3 * 5.5 = 155.7 m/s.

    V = V1 + g*t = 0
    155.7 - 9.8t = 0
    -9.8t = -155.7
    t = 15.9 s. To reach max ht.

    h2 = V1*t + 0.5g*t^2
    h2 = 155.7*15.9 - 4.9*15.9^2 = 1236 m
    Above h1.

    h = h1 + h2 = 856 + 1236 = 2092 m. Above gnd.

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