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If you have 13.0g of Na, how many grams of O2 are required for the reaction?

  • chemistry -

    If Na2O is formed it is
    4Na + O2 ==> 2Na2O

    mols Na = 13.0/atomic mass Na.
    mols O2 = 1/4 mols Na.
    g O2 = mols O2 x molar mass O2.

    If the reaction is the formation of Na2O2 then you have
    2Na + O2 --> Na2O2
    You can work it out from there, right?

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