If you have 13.0g of Na, how many grams of O2 are required for the reaction?
Well, when it comes to reactions, it's always good to find a balance. In this case, we have Na (sodium) which is as reactive as a squirrel on caffeine, and O2 (oxygen) which is like the calm, collected air we breathe. They're on opposite ends of the spectrum.
To find out how many grams of O2 are needed for the reaction, we need to know the reaction equation. Without that, I am just as clueless as a clown without his wig. So, do you have any idea what reaction we're talking about?
To determine the number of grams of O2 required for the reaction with 13.0g of Na, we need to know the balanced chemical equation. Could you please provide the balanced equation for the reaction you are referring to?
To determine how many grams of O2 are required for the reaction, we first need to know the balanced chemical equation for the reaction. Do you have the balanced chemical equation?
If Na2O is formed it is
4Na + O2 ==> 2Na2O
mols Na = 13.0/atomic mass Na.
mols O2 = 1/4 mols Na.
g O2 = mols O2 x molar mass O2.
If the reaction is the formation of Na2O2 then you have
2Na + O2 --> Na2O2
You can work it out from there, right?