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December 18, 2014

December 18, 2014

Posted by **Queta** on Tuesday, September 17, 2013 at 12:02pm.

A. g (x)= (x +13)^2

B. g (x)= ( x+8 )^2 +5

C. g (x)= x^2 -3

D. g (x)= x^2+13

I think (D.) is my answer please check over for me.

2. Determine the equation of g (x) that results from translating the functions f(x)= ( x+6 )^2 to the right 10 units.

A. g(x)= ( x-4 )^2

B. g(x)= (x+16)^2

C. g(x)= (x+6)^2-10

D. g(x)= (x+6)^2+10

I think the answer is (C).

3. Select the approximate values of x that are solutions to f(x)=0, where f(x)= -3 x ^2+4 x + 3

A. ( -1.00 , 1.33)

B. ( -3, 4 )

C. (-1.33 , -1.00 )

D. ( -0.54 , 1.87 )

I think the answer is (c).

3. Select the approximate values of x that are solutions to f(x)= 0, where f(x)= -9 x^2 + 3 x +3

A. ( 0.77 , -0.43 )

B. ( -9 , 3 )

C. ( -0.33 , -0.33 )

D. ( -3.00 , 1.00 )

I think the answer is (D).

4. Select the approximate values of x that are solutions to f (x)=0, where f(x)= -4 x^2 + 2 x +8.

A. ( - 1 .19 , 1.69 )

B. ( -4 , 2 )

C. ( -0.50 , -2.00 )

D. ( -0.50 , 0.25 )

I think the answer is (B).

Can someone please look over my work !!!

- Math help please!!! -
**Steve**, Tuesday, September 17, 2013 at 1:48pm#1 correct

#2 nope. (C) translates down 10 units

g(x-a) translates to the right by a units. So, we want g(x-10) = (x+6-10)^2 = (x-4)^2

(A)

#3 D? Really?

-9*3^2 +3(-3) + 3 = -81-9+3 is nowhere near 0.

The roots will be evenly spaced from x = -b/2a = 1/6 = .1667

So, (A) looks like a better choice.

#4 nope: -4*16 - 8 + 8 is nowhere near 0.

the roots will be equally distant from x = 1/8 = .125

So, (A)

Note: You may have to check further if there is more than one choice with the roots properly spaced.

- Math help please!!! -
**Mike**, Sunday, March 30, 2014 at 9:02pmDetermine the equation of g(x) that results from translating the function f(x) = x2 + 7 upward 12 units.

- Math help please!!! -
**star power**, Sunday, June 1, 2014 at 7:52amDetermine the equation of g(x) that results from translating the function f(x)=x^2+9 upward 12 units.

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