Tuesday

March 31, 2015

March 31, 2015

Posted by **Anonymous** on Tuesday, September 17, 2013 at 10:26am.

w=e^(2*pi*7/6)

so we have 6-th roots: 1,w,w^2,-1,-w,-w^2

My matrix is QFT6= 1/sqrt(6)*

(1 1 1 1 1 1 )

(1 w w^2 -1 -w -w^2)

(1 w^2 -w 1 w^2 -w )

(1 -1 1 -1 1 -1 )

(1 -w w^2 1 -w w^2 )

(1 -w^2 -w -1 w^2 w )

the vector that should be transformed is: 1/sqrt(2)* (|1> + |4>)

=1/sqrt(2)*(0 1 0 0 1 0)^T

if I multiply I get:

1/sqrt(3)*(1 0 w^2 0 -w 0)^T

there must be a mistake but I do not find it..

- Quantum Physics -
**Anonymous**, Tuesday, September 17, 2013 at 10:30amsorry.. w=e^(2*pi*i/6)

that was not the mistake just a type error ;)

- Quantum Physics -
**lal**, Sunday, September 22, 2013 at 12:41pmthe matrix u get

1/sqrt(3)*(1,0,w^2,0'-w,0)is right

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