Posted by Anonymous on Tuesday, September 17, 2013 at 10:26am.
I try to make a Quantum Fourier Transformation with N=6:
w=e^(2*pi*7/6)
so we have 6th roots: 1,w,w^2,1,w,w^2
My matrix is QFT6= 1/sqrt(6)*
(1 1 1 1 1 1 )
(1 w w^2 1 w w^2)
(1 w^2 w 1 w^2 w )
(1 1 1 1 1 1 )
(1 w w^2 1 w w^2 )
(1 w^2 w 1 w^2 w )
the vector that should be transformed is: 1/sqrt(2)* (1> + 4>)
=1/sqrt(2)*(0 1 0 0 1 0)^T
if I multiply I get:
1/sqrt(3)*(1 0 w^2 0 w 0)^T
there must be a mistake but I do not find it..

Quantum Physics  Anonymous, Tuesday, September 17, 2013 at 10:30am
sorry.. w=e^(2*pi*i/6)
that was not the mistake just a type error ;)

Quantum Physics  lal, Sunday, September 22, 2013 at 12:41pm
the matrix u get
1/sqrt(3)*(1,0,w^2,0'w,0)is right
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