Physics
posted by vv on .
Two balls, one of gold with a mass of 100 kg and one of wood with a mass of 1 kg, are suspended 1 meter apart. What is the attractive force, in newtons, of
a. the gold ball acting on the wooden ball?
b. the wooden ball acting on the gold ball?

a,b both forces are equal and opposite.
a. force=GMm/distance^2 
I solve it, but i don't know the sign of each one of them .. can you help me in this part please ..
F = (G.m1.m2) / (r2)
F = (6.673 x 1011 x 100 x 1) / (12)
F = 6.673 x 109 N