Posted by Nico on .
to find value of x and discontinous 9x²3x2/3x²+13x4

calculus 
Steve,
3x^2+13x4 = 0 when x = 1/6 (13±√217)
9x^23x2 = (3x2)(3x+1)
so, f(x) is discontinuous at x = 1/6 (13±√217) where the denominator is zero.