Tuesday

January 24, 2017
Posted by **Nico** on Tuesday, September 17, 2013 at 4:24am.

- calculus -
**Steve**, Tuesday, September 17, 2013 at 4:31am3x^2+13x-4 = 0 when x = -1/6 (13±√217)

9x^2-3x-2 = (3x-2)(3x+1)

so, f(x) is discontinuous at x = -1/6 (13±√217) where the denominator is zero.