Posted by Nico on Tuesday, September 17, 2013 at 4:24am.
3x^2+13x-4 = 0 when x = -1/6 (13±√217) 9x^2-3x-2 = (3x-2)(3x+1) so, f(x) is discontinuous at x = -1/6 (13±√217) where the denominator is zero.